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2(x^2+6)=7x
We move all terms to the left:
2(x^2+6)-(7x)=0
We add all the numbers together, and all the variables
-7x+2(x^2+6)=0
We multiply parentheses
2x^2-7x+12=0
a = 2; b = -7; c = +12;
Δ = b2-4ac
Δ = -72-4·2·12
Δ = -47
Delta is less than zero, so there is no solution for the equation
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